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<title type="245">Memorandum from Raymond L. Murray to Dr. Clifford K. Beck</title>
<title type="gmd">Machine readable transcription</title>
<author>Murray, Raymond L.</author>
<respStmt>
<resp>Creation of machine-readable version:</resp>
<name>Russell S. Koonts</name>
<resp>Creation of digital images:</resp>
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<pubPlace>Raleigh, NC</pubPlace>
<idno type="ETC"> Modern English, MurNBdecay123151</idno>
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<p>Available from: NC State University Archives</p>
<p>Publicly-accessible</p>
<p n="public">URL: http://www.lib.ncsu.edu/archives/etext/engineering/reactor/murray/</p>
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<date>24 October, 2000</date>
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<p>Nuclear Reactor Digitization Project</p>
<p>Raymond L. Murray Reactor Project Notebook</p>
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<title>Memorandum from Raymond L. Murray to Dr. Clifford K. Beck</title>
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<front><div1 type="summary" n="1">
<head><hi rend="bold"><hi rend="center">Memorandum from Raymond L. Murray to Dr. Clifford K. Beck</hi><lb/>
<bibl><abbr>Typescript</abbr><lb/> <extent>3 pp.</extent> <lb/><date value="1951-12-31">December 31, 1951</date><lb/> <idno rend="suppress">MurNBdecay123151</idno></bibl></hi></head>
<p>

</p>
</div1>
</front>

<body>
<pb n=""/>
<p><seg><xref id="reactorlg/MurNBdecay123151a.jpg" rend="new">
<figure entity="MurNBdecay123151a"></figure></xref></seg></p>
<div1 type="memorandum" n="1">
<head><hi rend="italics">Murray</hi></head>
<opener><dateline><date value="1951-12-31">December 31, 1951</date></dateline>
TO: <name type="person">Dr. Clifford K. Beck</name><lb/>
FROM: <name type="person">Raymond L. Murray</name><lb/>
CC:  Reactor Committee</opener>

<p>Since you pointed out that it was impractical to exhaust the contaminated<lb/>
gases from the reactor continuously (over a 24 hr. period.), it has been necessary<lb/>
to reconsider the analysis reported earlier. In addition, an alternative "transit<lb/>
time" method of estimating necessary holding volumes was proposed by <name type="person">Dr. Underwood</name><lb/>
that gave, a quite different form to the theory and calculated result. In this<lb/>
note it is shown that such qualitative approaches to the problem do not give the<lb/>
correct answer. An extension of the previous theory to the case of interrupted<lb/>
gas exhaust is provided.
</p>
<p>The final conclusion that is reached is that a factor of Xe concentration<lb/>
attenuation of greater than 10 is achieved by 8 tanks of 100 gallon capacity,<lb/>
assuming 6 hours per day 10 Kw reactor operation with 100 ml/hr air flow. A smaller<lb/>
total volume could be used if the number of tanks was increased and the individual<lb/>
tank size decreased.
</p>
<p><hi rend="underline">Transit Time Treatment Of Holding System</hi>.
</p>
<p>Assumptions:  Fluid is discharged at a rate v into and out of a container of volume<lb/>
V.  Two possible modes of transfer through the container are (a) steady flow,<lb/>
(b) flow with complete mixing.
</p>
<p>Case (a) Regardless of the dimensions of the system, the time &#x00AF;t  for a given<lb/>
sample of fluid to traverse the system is given by V/v. (Assume a length of total<lb/>
path L, area A, then &#x00AF;t = L/u where u is the flow speed. However u A = v, so &#x00AF;t =<lb/>
LA/v = V/v).
</p>

<p>Case (b) The rate at which particles of fluid leave the system is dN/dt=-&#x03C1;v<lb/>
where &#x03C1; is the no. per unit volume of the selected group, and is N/V. Thus dN/dt = -Nf<lb/>
where f = v/V. Let &#x03C8;(t)dt = <hi rend="sup">|dN|</hi>/<hi rend="sub">N<hi rend="sub">o</hi></hi> be the distribution function for transit times.<lb/>
Since N = N<hi rend="sub">o</hi>e<hi rend="sup">-ft</hi>, &#x03C8;(t) = fe<hi rend="sup">-ft</hi>. The mean time is <hi rend='suppress'><formula notation='mathml'>
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<seg rend='left'><figure entity="MurNBdecay123151form1"></figure></seg> By simple analogy<lb/>
with the computation of mean free paths by integration, &#x00AF;t = l/f = V/v as in case (a)<lb/>
</p>
<p><hi rend="underline">Extension to Radioactive <orig reg="Decay">Deacy</orig></hi>: The concentration of exhaust fluid would be<lb/>
expected to be reduced by a factor e<hi rend="sup">-&#x03BB;&#x00AF;t</hi> if the mean holding time is &#x00AF;t. Thus<lb/>
C<hi rend="sub">f</hi>/C<hi rend="sub">o</hi> the ratio of concentrations would be<lb/>
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<seg rend='left'><figure entity="MurNBdecay123151form2"></figure></seg>
  
<lb/>
This result would be obtained whether V was composed of n smaller tanks of volume<lb/>
V<hi rend="sub">l</hi>,or one large tank of volume n V<hi rend="sub">l</hi>.
</p>
<p>The transit time analysis is applicable to a case in which the radioactive gas<lb/>
decays into a stable gas which also continues through the system of containers.<lb/>
In the actual situation, the Xe decays into Cs, which will be largely trapped by<lb/>
the water chamber walls, etc. The fallacy that is embodied in the transit time<lb/>
approach is thus readily seen. The average transit time would have to include<lb/>
all those Cs atoms which are stopped; ie., have infinite lifetime in the system.<lb/>
Thus it appears that the differential equations approach is more realistic, and so<lb/>
far as is determined, correct. The revision in calculation by the latter method<lb/>
follows.
</p>
<pb n=""/>
<p><seg><xref id="reactorlg/MurNBdecay123151b.jpg" rend="new">
<figure entity="MurNBdecay123151b"></figure></xref></seg></p>
<p><hi rend="underline">REVISED METHOD OF CALCULATION OF SERIES HOLDING EFFECTS</hi>
</p>
<p>In an earlier report<ptr target="a1"/>, the reduction of Xe concentration in a sequence of<lb/>
holding tanks was calculated on the assumption that the discharge was continuous.<lb/>
The result found was that there was an attenuation of a factor <hi rend='suppress'><formula notation='mathml'>
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</formula></hi>
<seg rend='left'><figure entity="MurNBdecay123151form3"></figure></seg> where &#x03BB;<lb/>
is the decay constant in inverse days, and f was the ratio of air volume <orig reg="accumulated">accumu-<lb/>
lated</orig> and discharged per day v to the volume of individual tanks, and n was the<lb/>
number of such tanks. Since it was decided to release active air only during the<lb/>
period the reactor is operating, a new approach to the problem was made.
</p>
<p>
<list>
<item>1. Air containing Xe is delivered to the first tank, volume V of the holding<lb/>
system, at a concentration C<hi rend="sub">o</hi>, at a rate v liters per day, for the reactor <orig reg="operation">ope-<lb/>
ration</orig> time. If the total activity to be eliminated is A, then C<hi rend="sub">o</hi> = A/v&#x03C4;
</item>
<item><lb/></item>
<item>2. The concentration C<hi rend="sub">l</hi> of discharge from the first tank during the period &#x03C4;<lb/>
is governed by the equation <hi rend="sup">dC<hi rend="sub">l</hi></hi>/<hi rend="sub">dt</hi> = C<hi rend="sub">o</hi>f - C<hi rend="sub">l</hi> (&#x03BB;+ f) where f is the ratio v/V.
</item>
<item><lb/></item>
<item>3. The solution of the above equation, applicable for o &lt; t &lt; &#x03C4; is<lb/>
<hi rend='suppress'><formula notation='mathml'>
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<seg rend='left'><figure entity="MurNBdecay123151form4"></figure></seg>
</item>
<item><lb/></item>
<item>4. The concentration in the tank subsequent to time &#x03C4; is given by<lb/>
<hi rend='suppress'><formula notation='mathml'>
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<seg rend='left'><figure entity="MurNBdecay123151form5"></figure></seg>
</item>
<item><lb/></item>
<item>5. The contributions of all previous operation cycles may be added by forming<lb/>
the sum<lb/>
<hi rend='suppress'><formula notation='mathml'>
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<seg rend='left'><figure entity="MurNBdecay123151form6"></figure></seg><lb/>
where the integer i signifies a shift in time of i days necessary to pick up<lb/>
previous days' effects.<lb/>
<lb/>
The geometric series is summed as follows:<lb/>
<hi rend='suppress'><formula notation='mathml'>
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        </msup>
      </mrow>
    </mfrac>
  </mrow>
</m:math>
-->
</formula></hi>
<seg rend='left'><figure entity="MurNBdecay123151form7"></figure></seg><lb/>
Thus the concentration for continued but intermittent operation is a factor<lb/>
<hi rend="sup">1</hi>/<hi rend="sub">1-e<hi rend="sup">-&#x03BB;</hi></hi> than that due to one cycle.
</item>
<item><lb/></item>
<item>6. The maximum value of concentration ratio C<hi rend="sub">l</hi>/C<hi rend="sub">o</hi> is thus<lb/>
<hi rend='suppress'><formula notation='mathml'>
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        <mrow>
          <msub>
            <mrow>
              <mi>C</mi>
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      <mo>=</mo>
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            <mrow>
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      <mi>&thinsp;</mi>
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          <msup>
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              <mi>e</mi>
            </mrow>
            <mrow>
              <mo>-</mo>
              <mi>&lambda;</mi>
              <mi>l</mi>
              <mi>&tau;</mi>
            </mrow>
          </msup>
        </mrow>
        <mrow>
          <mn>1</mn>
          <mo>-</mo>
          <msup>
            <mrow>
              <mi>e</mi>
            </mrow>
            <mrow>
              <mo>-</mo>
              <mi>&lambda;</mi>
            </mrow>
          </msup>
        </mrow>
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      <mi>&thinsp;</mi>
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      <mi>B</mi>
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        <mrow>
          <mi>f</mi>
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        <mrow>
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              <mi>&lambda;</mi>
            </mrow>
            <mrow>
              <mi>l</mi>
            </mrow>
          </msup>
        </mrow>
      </mfrac>
    </mrow>
  </mrow>
</m:math>
-->
</formula></hi>
<seg rend='left'><figure entity="MurNBdecay123151form8"></figure></seg><lb/>
Where B is the function indicated.
</item>
<item><lb/></item>
<item>7. It is assumed by analogy with the previous derivation that the effect of<lb/>
n tanks is to raise this factor to the power n.<lb/>
<table>
<row><cell>Example:</cell><cell>v = 100 ml/min = 144 liters/day</cell></row>
<row><cell></cell><cell>V = 100 gallons = 378.5 liters</cell></row>
<row><cell></cell><cell>&#x03BB; = 0.331 days<hi rend="sup">-1</hi></cell></row>
<row><cell></cell><cell>f = v/V = 0.380</cell></row>
</table>
</item>
</list>
</p>
<pb n=""/>
<p><seg><xref id="reactorlg/MurNBdecay123151c.jpg" rend="new">
<figure entity="MurNBdecay123151c"></figure></xref></seg></p>

<p><list><item><table>
<row>
<cell></cell><cell>&#x03BB;<hi rend="sup">l</hi> = 0.511</cell>
</row>
<row>
<cell></cell><cell>&#x03C4; = 0.25 days (6 hours)</cell>
</row>
<row>
<cell></cell><cell>&#x03BB;<hi rend="sup">l</hi>&#x03C4; = 0.128</cell>
</row>
</table></item></list>
Thus B =
<hi rend='suppress'><formula notation='mathml'>
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        <mrow>
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      </mfrac>
    </mrow>
  </mrow>
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-->
</formula></hi>
<seg rend='left'><figure entity="MurNBdecay123151form9"></figure></seg> = 0.978<lb/>
<hi rend="sup">f</hi>/<hi rend="sub">&#x03BB;<hi rend="sup">l</hi></hi> =  0.744<lb/>
<hi rend="sup">C<hi rend="sub">l</hi></hi>/<hi rend="sub">C<hi rend="sub">o</hi></hi> =  0.728
</p>
<p>In order to achieve en attenuation of 10, the number of tanks must be that for<lb/>
which (0.728)<hi rend="sup">n</hi> = 0.1 or
<hi rend='suppress'><formula notation='mathml'>
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      <mi>n</mi>
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      <mi>&thinsp;</mi>
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</formula></hi>
<seg rend='left'><figure entity="MurNBdecay123151form10"></figure></seg> or conservatively n = 8.
</p>
<p>It is interesting to note that the predicted attenuation by transit time theory<lb/>
is attained only by an infinite array of infinitesimal tanks, as shown below:<lb/>
Let
<hi rend='suppress'><formula notation='mathml'>
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            <mrow>
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      <mo>=</mo>
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                  <mi>&lambda;</mi>
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              </mfrac>
              <mo>)</mo>
            </mrow>
          </mrow>
          <mrow>
            <mi>n</mi>
          </mrow>
        </msup>
        <mi>&thinsp;</mi>
        <mi>&thinsp;</mi>
        <mi>&thinsp;</mi>
        <mi>&thinsp;</mi>
        <mrow>
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          <mo>&cong;</mo>
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        </mrow>
      </mrow>
    </mrow>
  </mrow>
</m:math>
-->
</formula></hi>
<seg rend='left'><figure entity="MurNBdecay123151form11"></figure></seg>
</p>
<p>Fix the total volume V<hi rend="sub">T</hi> = n V, so that the above ratio becomes
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              <mi>n</mi>
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      </mfrac>
    </mrow>
  </mrow>
</m:math>
-->
</formula></hi>
<seg rend='left'><figure entity="MurNBdecay123151form12"></figure></seg><lb/>
the limit of which as n goes to 
<hi rend='suppress'><formula notation='mathml'>
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          <mi>&lambda;</mi>
        </mrow>
      </mfrac>
    </mrow>
  </mrow>
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-->
</formula></hi>
<seg rend='left'><figure entity="MurNBdecay123151form13"></figure></seg>
</p>
<p>One other case besides that of continuous discharge may be analyzed by the same<lb/>
method: Assume that contaminated air is let in for a period &#x03C4;, but the system<lb/>
is flushed with pure air for a period 1 - &#x03C4;.
<list><item>The multiplying factor B now involves the "total" decay constant<lb/>
&#x03BB;<hi rend="sup">l</hi> = &#x03BB; + f in the denominator rather then just &#x03BB;. The attenuation per tank<lb/>
is reduced by
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      <mo>&cong;</mo>
      <mn>0</mn>
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      <mn>0</mn>
    </mrow>
  </mrow>
</m:math>
-->
</formula></hi>
<seg rend='left'><figure entity="MurNBdecay123151form14"></figure></seg><lb/>
which makes the system much more favorable. With 8 tanks, an additional<lb/>
reduction of (0.3)<hi rend="sup">8</hi> = 6.6 x 10<hi rend="sup">-5</hi> is obtained. Qualitatively, the reason<lb/>
for this improvement is that "physical" decay characterized by f is much<lb/>
stronger than radioactive decay.
</item></list></p>
</div1>
</body>
<back>
<div1 type="notes" n="1">
<p><anchor id="a1"/>Memo to <name type="person">C.K. Beck</name>, <title><hi rend="underline">Effectiveness of Series Holding System for Radioactive<lb/>Gases</hi></title>
</p>

</div1>
</back></text>
</TEI.2>